Integrand size = 26, antiderivative size = 129 \[ \int \frac {(d+e x)^5}{\left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=\frac {e^4 (5 b d-4 a e) x}{b^5}+\frac {e^5 x^2}{2 b^4}-\frac {(b d-a e)^5}{3 b^6 (a+b x)^3}-\frac {5 e (b d-a e)^4}{2 b^6 (a+b x)^2}-\frac {10 e^2 (b d-a e)^3}{b^6 (a+b x)}+\frac {10 e^3 (b d-a e)^2 \log (a+b x)}{b^6} \]
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Time = 0.09 (sec) , antiderivative size = 129, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {27, 45} \[ \int \frac {(d+e x)^5}{\left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=\frac {10 e^3 (b d-a e)^2 \log (a+b x)}{b^6}-\frac {10 e^2 (b d-a e)^3}{b^6 (a+b x)}-\frac {5 e (b d-a e)^4}{2 b^6 (a+b x)^2}-\frac {(b d-a e)^5}{3 b^6 (a+b x)^3}+\frac {e^4 x (5 b d-4 a e)}{b^5}+\frac {e^5 x^2}{2 b^4} \]
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Rule 27
Rule 45
Rubi steps \begin{align*} \text {integral}& = \int \frac {(d+e x)^5}{(a+b x)^4} \, dx \\ & = \int \left (\frac {e^4 (5 b d-4 a e)}{b^5}+\frac {e^5 x}{b^4}+\frac {(b d-a e)^5}{b^5 (a+b x)^4}+\frac {5 e (b d-a e)^4}{b^5 (a+b x)^3}+\frac {10 e^2 (b d-a e)^3}{b^5 (a+b x)^2}+\frac {10 e^3 (b d-a e)^2}{b^5 (a+b x)}\right ) \, dx \\ & = \frac {e^4 (5 b d-4 a e) x}{b^5}+\frac {e^5 x^2}{2 b^4}-\frac {(b d-a e)^5}{3 b^6 (a+b x)^3}-\frac {5 e (b d-a e)^4}{2 b^6 (a+b x)^2}-\frac {10 e^2 (b d-a e)^3}{b^6 (a+b x)}+\frac {10 e^3 (b d-a e)^2 \log (a+b x)}{b^6} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 228, normalized size of antiderivative = 1.77 \[ \int \frac {(d+e x)^5}{\left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=\frac {47 a^5 e^5+a^4 b e^4 (-130 d+81 e x)+a^3 b^2 e^3 \left (110 d^2-270 d e x-9 e^2 x^2\right )-a^2 b^3 e^2 \left (20 d^3-270 d^2 e x+90 d e^2 x^2+63 e^3 x^3\right )-5 a b^4 e \left (d^4+12 d^3 e x-36 d^2 e^2 x^2-18 d e^3 x^3+3 e^4 x^4\right )+b^5 \left (-2 d^5-15 d^4 e x-60 d^3 e^2 x^2+30 d e^4 x^4+3 e^5 x^5\right )+60 e^3 (b d-a e)^2 (a+b x)^3 \log (a+b x)}{6 b^6 (a+b x)^3} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(251\) vs. \(2(123)=246\).
Time = 2.30 (sec) , antiderivative size = 252, normalized size of antiderivative = 1.95
method | result | size |
default | \(-\frac {e^{4} \left (-\frac {1}{2} b e \,x^{2}+4 a e x -5 b d x \right )}{b^{5}}-\frac {-a^{5} e^{5}+5 a^{4} b d \,e^{4}-10 a^{3} b^{2} d^{2} e^{3}+10 a^{2} b^{3} d^{3} e^{2}-5 a \,b^{4} d^{4} e +b^{5} d^{5}}{3 b^{6} \left (b x +a \right )^{3}}+\frac {10 e^{3} \left (a^{2} e^{2}-2 a b d e +b^{2} d^{2}\right ) \ln \left (b x +a \right )}{b^{6}}-\frac {5 e \left (e^{4} a^{4}-4 b \,e^{3} d \,a^{3}+6 b^{2} e^{2} d^{2} a^{2}-4 a \,b^{3} d^{3} e +b^{4} d^{4}\right )}{2 b^{6} \left (b x +a \right )^{2}}+\frac {10 e^{2} \left (a^{3} e^{3}-3 a^{2} b d \,e^{2}+3 a \,b^{2} d^{2} e -b^{3} d^{3}\right )}{b^{6} \left (b x +a \right )}\) | \(252\) |
norman | \(\frac {\frac {\left (30 a^{3} e^{5}-60 a^{2} b d \,e^{4}+30 a \,b^{2} d^{2} e^{3}-10 b^{3} d^{3} e^{2}\right ) x^{2}}{b^{4}}+\frac {110 a^{5} e^{5}-220 a^{4} b d \,e^{4}+110 a^{3} b^{2} d^{2} e^{3}-20 a^{2} b^{3} d^{3} e^{2}-5 a \,b^{4} d^{4} e -2 b^{5} d^{5}}{6 b^{6}}+\frac {e^{5} x^{5}}{2 b}+\frac {\left (90 e^{5} a^{4}-180 a^{3} b d \,e^{4}+90 a^{2} b^{2} d^{2} e^{3}-20 a \,b^{3} d^{3} e^{2}-5 b^{4} d^{4} e \right ) x}{2 b^{5}}-\frac {5 e^{4} \left (a e -2 b d \right ) x^{4}}{2 b^{2}}}{\left (b x +a \right )^{3}}+\frac {10 e^{3} \left (a^{2} e^{2}-2 a b d e +b^{2} d^{2}\right ) \ln \left (b x +a \right )}{b^{6}}\) | \(255\) |
risch | \(\frac {e^{5} x^{2}}{2 b^{4}}-\frac {4 e^{5} a x}{b^{5}}+\frac {5 e^{4} d x}{b^{4}}+\frac {\left (10 a^{3} b \,e^{5}-30 a^{2} b^{2} d \,e^{4}+30 a \,b^{3} d^{2} e^{3}-10 b^{4} d^{3} e^{2}\right ) x^{2}+\frac {5 e \left (7 e^{4} a^{4}-20 b \,e^{3} d \,a^{3}+18 b^{2} e^{2} d^{2} a^{2}-4 a \,b^{3} d^{3} e -b^{4} d^{4}\right ) x}{2}+\frac {47 a^{5} e^{5}-130 a^{4} b d \,e^{4}+110 a^{3} b^{2} d^{2} e^{3}-20 a^{2} b^{3} d^{3} e^{2}-5 a \,b^{4} d^{4} e -2 b^{5} d^{5}}{6 b}}{b^{5} \left (b^{2} x^{2}+2 a b x +a^{2}\right ) \left (b x +a \right )}+\frac {10 e^{5} \ln \left (b x +a \right ) a^{2}}{b^{6}}-\frac {20 e^{4} \ln \left (b x +a \right ) a d}{b^{5}}+\frac {10 e^{3} \ln \left (b x +a \right ) d^{2}}{b^{4}}\) | \(287\) |
parallelrisch | \(\frac {-2 b^{5} d^{5}+110 a^{5} e^{5}-220 a^{4} b d \,e^{4}+110 a^{3} b^{2} d^{2} e^{3}-20 a^{2} b^{3} d^{3} e^{2}-5 a \,b^{4} d^{4} e -540 a^{3} b^{2} d \,e^{4} x -360 \ln \left (b x +a \right ) x^{2} a^{2} b^{3} d \,e^{4}+180 \ln \left (b x +a \right ) x^{2} a \,b^{4} d^{2} e^{3}+270 a^{4} b \,e^{5} x -360 x^{2} a^{2} b^{3} d \,e^{4}+180 x^{2} a \,b^{4} d^{2} e^{3}+180 \ln \left (b x +a \right ) x \,a^{4} b \,e^{5}-120 \ln \left (b x +a \right ) a^{4} b d \,e^{4}-120 \ln \left (b x +a \right ) x^{3} a \,b^{4} d \,e^{4}+180 \ln \left (b x +a \right ) x \,a^{2} b^{3} d^{2} e^{3}-360 \ln \left (b x +a \right ) x \,a^{3} b^{2} d \,e^{4}+60 \ln \left (b x +a \right ) a^{3} b^{2} d^{2} e^{3}+30 x^{4} b^{5} d \,e^{4}-15 b^{5} d^{4} e x +3 x^{5} e^{5} b^{5}+60 \ln \left (b x +a \right ) a^{5} e^{5}-15 x^{4} a \,b^{4} e^{5}+60 \ln \left (b x +a \right ) x^{3} a^{2} b^{3} e^{5}+60 \ln \left (b x +a \right ) x^{3} b^{5} d^{2} e^{3}+180 \ln \left (b x +a \right ) x^{2} a^{3} b^{2} e^{5}+180 x^{2} a^{3} b^{2} e^{5}-60 x^{2} b^{5} d^{3} e^{2}+270 x \,a^{2} b^{3} d^{2} e^{3}-60 x a \,b^{4} d^{3} e^{2}}{6 b^{6} \left (b^{2} x^{2}+2 a b x +a^{2}\right ) \left (b x +a \right )}\) | \(477\) |
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Leaf count of result is larger than twice the leaf count of optimal. 426 vs. \(2 (123) = 246\).
Time = 0.33 (sec) , antiderivative size = 426, normalized size of antiderivative = 3.30 \[ \int \frac {(d+e x)^5}{\left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=\frac {3 \, b^{5} e^{5} x^{5} - 2 \, b^{5} d^{5} - 5 \, a b^{4} d^{4} e - 20 \, a^{2} b^{3} d^{3} e^{2} + 110 \, a^{3} b^{2} d^{2} e^{3} - 130 \, a^{4} b d e^{4} + 47 \, a^{5} e^{5} + 15 \, {\left (2 \, b^{5} d e^{4} - a b^{4} e^{5}\right )} x^{4} + 9 \, {\left (10 \, a b^{4} d e^{4} - 7 \, a^{2} b^{3} e^{5}\right )} x^{3} - 3 \, {\left (20 \, b^{5} d^{3} e^{2} - 60 \, a b^{4} d^{2} e^{3} + 30 \, a^{2} b^{3} d e^{4} + 3 \, a^{3} b^{2} e^{5}\right )} x^{2} - 3 \, {\left (5 \, b^{5} d^{4} e + 20 \, a b^{4} d^{3} e^{2} - 90 \, a^{2} b^{3} d^{2} e^{3} + 90 \, a^{3} b^{2} d e^{4} - 27 \, a^{4} b e^{5}\right )} x + 60 \, {\left (a^{3} b^{2} d^{2} e^{3} - 2 \, a^{4} b d e^{4} + a^{5} e^{5} + {\left (b^{5} d^{2} e^{3} - 2 \, a b^{4} d e^{4} + a^{2} b^{3} e^{5}\right )} x^{3} + 3 \, {\left (a b^{4} d^{2} e^{3} - 2 \, a^{2} b^{3} d e^{4} + a^{3} b^{2} e^{5}\right )} x^{2} + 3 \, {\left (a^{2} b^{3} d^{2} e^{3} - 2 \, a^{3} b^{2} d e^{4} + a^{4} b e^{5}\right )} x\right )} \log \left (b x + a\right )}{6 \, {\left (b^{9} x^{3} + 3 \, a b^{8} x^{2} + 3 \, a^{2} b^{7} x + a^{3} b^{6}\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 284 vs. \(2 (119) = 238\).
Time = 1.73 (sec) , antiderivative size = 284, normalized size of antiderivative = 2.20 \[ \int \frac {(d+e x)^5}{\left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=x \left (- \frac {4 a e^{5}}{b^{5}} + \frac {5 d e^{4}}{b^{4}}\right ) + \frac {47 a^{5} e^{5} - 130 a^{4} b d e^{4} + 110 a^{3} b^{2} d^{2} e^{3} - 20 a^{2} b^{3} d^{3} e^{2} - 5 a b^{4} d^{4} e - 2 b^{5} d^{5} + x^{2} \cdot \left (60 a^{3} b^{2} e^{5} - 180 a^{2} b^{3} d e^{4} + 180 a b^{4} d^{2} e^{3} - 60 b^{5} d^{3} e^{2}\right ) + x \left (105 a^{4} b e^{5} - 300 a^{3} b^{2} d e^{4} + 270 a^{2} b^{3} d^{2} e^{3} - 60 a b^{4} d^{3} e^{2} - 15 b^{5} d^{4} e\right )}{6 a^{3} b^{6} + 18 a^{2} b^{7} x + 18 a b^{8} x^{2} + 6 b^{9} x^{3}} + \frac {e^{5} x^{2}}{2 b^{4}} + \frac {10 e^{3} \left (a e - b d\right )^{2} \log {\left (a + b x \right )}}{b^{6}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 281 vs. \(2 (123) = 246\).
Time = 0.22 (sec) , antiderivative size = 281, normalized size of antiderivative = 2.18 \[ \int \frac {(d+e x)^5}{\left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=-\frac {2 \, b^{5} d^{5} + 5 \, a b^{4} d^{4} e + 20 \, a^{2} b^{3} d^{3} e^{2} - 110 \, a^{3} b^{2} d^{2} e^{3} + 130 \, a^{4} b d e^{4} - 47 \, a^{5} e^{5} + 60 \, {\left (b^{5} d^{3} e^{2} - 3 \, a b^{4} d^{2} e^{3} + 3 \, a^{2} b^{3} d e^{4} - a^{3} b^{2} e^{5}\right )} x^{2} + 15 \, {\left (b^{5} d^{4} e + 4 \, a b^{4} d^{3} e^{2} - 18 \, a^{2} b^{3} d^{2} e^{3} + 20 \, a^{3} b^{2} d e^{4} - 7 \, a^{4} b e^{5}\right )} x}{6 \, {\left (b^{9} x^{3} + 3 \, a b^{8} x^{2} + 3 \, a^{2} b^{7} x + a^{3} b^{6}\right )}} + \frac {b e^{5} x^{2} + 2 \, {\left (5 \, b d e^{4} - 4 \, a e^{5}\right )} x}{2 \, b^{5}} + \frac {10 \, {\left (b^{2} d^{2} e^{3} - 2 \, a b d e^{4} + a^{2} e^{5}\right )} \log \left (b x + a\right )}{b^{6}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 262 vs. \(2 (123) = 246\).
Time = 0.25 (sec) , antiderivative size = 262, normalized size of antiderivative = 2.03 \[ \int \frac {(d+e x)^5}{\left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=\frac {10 \, {\left (b^{2} d^{2} e^{3} - 2 \, a b d e^{4} + a^{2} e^{5}\right )} \log \left ({\left | b x + a \right |}\right )}{b^{6}} + \frac {b^{4} e^{5} x^{2} + 10 \, b^{4} d e^{4} x - 8 \, a b^{3} e^{5} x}{2 \, b^{8}} - \frac {2 \, b^{5} d^{5} + 5 \, a b^{4} d^{4} e + 20 \, a^{2} b^{3} d^{3} e^{2} - 110 \, a^{3} b^{2} d^{2} e^{3} + 130 \, a^{4} b d e^{4} - 47 \, a^{5} e^{5} + 60 \, {\left (b^{5} d^{3} e^{2} - 3 \, a b^{4} d^{2} e^{3} + 3 \, a^{2} b^{3} d e^{4} - a^{3} b^{2} e^{5}\right )} x^{2} + 15 \, {\left (b^{5} d^{4} e + 4 \, a b^{4} d^{3} e^{2} - 18 \, a^{2} b^{3} d^{2} e^{3} + 20 \, a^{3} b^{2} d e^{4} - 7 \, a^{4} b e^{5}\right )} x}{6 \, {\left (b x + a\right )}^{3} b^{6}} \]
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Time = 0.13 (sec) , antiderivative size = 286, normalized size of antiderivative = 2.22 \[ \int \frac {(d+e x)^5}{\left (a^2+2 a b x+b^2 x^2\right )^2} \, dx=\frac {e^5\,x^2}{2\,b^4}-x\,\left (\frac {4\,a\,e^5}{b^5}-\frac {5\,d\,e^4}{b^4}\right )-\frac {\frac {-47\,a^5\,e^5+130\,a^4\,b\,d\,e^4-110\,a^3\,b^2\,d^2\,e^3+20\,a^2\,b^3\,d^3\,e^2+5\,a\,b^4\,d^4\,e+2\,b^5\,d^5}{6\,b}+x\,\left (-\frac {35\,a^4\,e^5}{2}+50\,a^3\,b\,d\,e^4-45\,a^2\,b^2\,d^2\,e^3+10\,a\,b^3\,d^3\,e^2+\frac {5\,b^4\,d^4\,e}{2}\right )-x^2\,\left (10\,a^3\,b\,e^5-30\,a^2\,b^2\,d\,e^4+30\,a\,b^3\,d^2\,e^3-10\,b^4\,d^3\,e^2\right )}{a^3\,b^5+3\,a^2\,b^6\,x+3\,a\,b^7\,x^2+b^8\,x^3}+\frac {\ln \left (a+b\,x\right )\,\left (10\,a^2\,e^5-20\,a\,b\,d\,e^4+10\,b^2\,d^2\,e^3\right )}{b^6} \]
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